What is the area of a trapezoid with bases of 10 cm and 6 cm, and a height of 4 cm?

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Multiple Choice

What is the area of a trapezoid with bases of 10 cm and 6 cm, and a height of 4 cm?

Explanation:
To find the area of a trapezoid, you can use the formula: \[ \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h \] where \(b_1\) and \(b_2\) are the lengths of the two bases, and \(h\) is the height. In this case, the bases are 10 cm and 6 cm, while the height is 4 cm. First, add the lengths of the bases: \[ b_1 + b_2 = 10 \, \text{cm} + 6 \, \text{cm} = 16 \, \text{cm} \] Now, plug this value into the area formula along with the height: \[ \text{Area} = \frac{1}{2} \times 16 \, \text{cm} \times 4 \, \text{cm} \] Calculating this step-by-step: \[ \text{Area} = \frac{1}{2} \times 16 \times 4 = 8 \times 4 = 32 \, \text{

To find the area of a trapezoid, you can use the formula:

[

\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h

]

where (b_1) and (b_2) are the lengths of the two bases, and (h) is the height. In this case, the bases are 10 cm and 6 cm, while the height is 4 cm.

First, add the lengths of the bases:

[

b_1 + b_2 = 10 , \text{cm} + 6 , \text{cm} = 16 , \text{cm}

]

Now, plug this value into the area formula along with the height:

[

\text{Area} = \frac{1}{2} \times 16 , \text{cm} \times 4 , \text{cm}

]

Calculating this step-by-step:

[

\text{Area} = \frac{1}{2} \times 16 \times 4 = 8 \times 4 = 32 , \text{

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